Range: 9
Mean: 12.43
Median: 12
Mode: 9
median= 4&3 range=3 mode= no mode
range
mean= 2, mode= 1 and 3, median= 3, and range= 2
Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6
mean: 60 median: 56.5 mode: 56 range: [48,75]
What is the answer
median= 4&3 range=3 mode= no mode
Median = 58 Mode = 58 Range = 0
The mean is 1226.75. The median is 508. There is no mode, as each number is different.
Subtracting the same amount from each value in a data set decreases the **mean**, *median*, and **mode** by that amount, but the **range** remains unchanged.
No because the range , median, and mode are all diffrent things to find the range subtract the largest and smallest number in the list , to find the median list the numbers in order then cross them out with pairs at the end and beginning of the list, and to find the MODE you just look at the number that appears there MOST times. O.K.
Calculate the mean, median, and range with the outlier, and then again without the outlier. Then find the difference. Mode will be unaffected by an outlier.
Yes. They must have a range and median. They may or may not have a mode.
The range is 20, the median is 80, and the mode is 80.
Median means average, and range is the range of numbers in a group. For example, the range is from 52 to 71. I don't know what a mode is.
The mean, median and mode of a single number is the number itself. The range is 0.
Mean: 71 Median: 67.5 Mode: None Range: 28