Odds against A = Probabillity against A / Probability for A Odds against A = (1 - Probabillity for A) / Probability for A 9.8 = (1 - Probabillity for A) / Probability for A 9.8 * Probability for A = 1 - Probability for A 10.8 * Probability for A = 1 Probability for A = 1 / 10.8 Probability for A = 0.0926
For 5 to 3 odds of winning; the probability of winning is 0.375 or 37.5%
Just take the probability, which is a decimal number between 0 and 1, and convert it into a fraction. For instance, a probability of 0.75 corresponds to odds of 3 in 4.
For 9 to 11 odds of winning;Probability of winning:0.55, or;Chance of winning:55%
Answerodds the odds in favour are p/(1-p)the odds against are (1-p)/p
Odds against A = Probabillity against A / Probability for A Odds against A = (1 - Probabillity for A) / Probability for A 9.8 = (1 - Probabillity for A) / Probability for A 9.8 * Probability for A = 1 - Probability for A 10.8 * Probability for A = 1 Probability for A = 1 / 10.8 Probability for A = 0.0926
For 5 to 3 odds of winning; the probability of winning is 0.375 or 37.5%
No, but they are related. Suppose an experiment is repeated N times, and X outcomes are favourable to the event A. Then the probability of A is X/N The odds for A are X/(N - X) Note that (N-X) are the number of outcomes that are favourable to "not-A".
Your "odds" are your likelihood or probability of winning.
Probability is a numeric expression of the "odds" that something will happen.
Just take the probability, which is a decimal number between 0 and 1, and convert it into a fraction. For instance, a probability of 0.75 corresponds to odds of 3 in 4.
For 9 to 11 odds of winning;Probability of winning:0.55, or;Chance of winning:55%
Odds.
Yes
Answerodds the odds in favour are p/(1-p)the odds against are (1-p)/p
Yes decimals are used in probability; also percent and odds.
The probability is 4/15