No.
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3
If you want 4-digit numbers, there are 24 of them.
20
In number systems , we can divide 3 digit number or 2 digit number by 1 . By the simple division method and the answer will always be the number itself. It will give the value 3 digit number. For eg, 100/ 1 =100 and 1/100 is 0.01 which is a decimal number.
No.
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
Yes. By 1 digit, 2 digit and some even by other 3 digit numbers.
-1
No You Divide All The 3 numbers by the two and do the math and that's your answer.
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
There are no such numbers.
3 digit numbers are lessthan 4 digit numbers
-1
2
mathematics