The number of 3 letter different combinations that can be made from 10 different
letters is given by: 10C3 = 10!/[3!(10-3)!] = 120different 3 letter combinations.
The number of three letter different permutations (one given 3 letter combination
gives 3! = 6 different permutations, e.g., the combination abc gives the 9
permutations, abc, acb, bac, cab, bca, cba) is given by 10P3 = 10!/(10-3)! = 720
different 3 letter permutations.
The symbol (!) is the operator called "factorial" and it implies the multiplication:
n! = n∙(n-1)! = n∙(n-1)∙(n-2)! = n(n-1)(n-2)(n-3)...(4)(3)(2)(1)(0!)
where 0! = 1.
i.g., 6! = 6∙5∙4∙3∙2∙1 = 720
17,576 possible combinations * * * * * Not quite! This is the total number of permutations of 3 letters out of 26. AAB is counted as being different from ABA or BAA. But these are the same combinations. Thus there are 26 combinations of just one letter. 26*25 combinations of two letters and 26*25*24/(3*2*1) of three. In all, that makes 26 + 650 + 2600 = 3276
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
Taking this bit by bit... For each number there are 10 possibilities so three numbers has 10^3 which is 1000 for each letter there are 26 choices, so for three letters you have 26^3 which is 17576 together there are 17576 * 1000 options which makes 17576000 possible combinations of letters and numbers and I suspect that is what you want. However if the order of the combination is important you must take into account the position of each letter/number and remove duplicate combinations. Good luck with that
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
There are 120 ways to order a 5 letter word, however, since there are two "e" letters in the word "green", the number of combinations is only 60.
6
12
No is a word. On is a word.
Four combinations: tam ham mat hat Hope it helps (:!
20
3,124,550 possible combinations
4
There are many word combinations for these letters, IUEDNVHS, but no one word can be made from these 8 letters.
Because there are 7 letters that don't repeat, 7X6X5X4=840 combinations. To give you an idea of how to solve the problem, if there had been 9 letters and you wanted to make combinations of 3 letters, you would multiply: 9X8X7=504
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
5. One each with one of the 5 letters left out: abcd, abce, abde, acde and bcde.