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How many 4 digit even numbers are there if numbers can be repeated?
Wiki User
∙ 12y ago
Assuming that the second instance of "numbers" in the question means "digits", the answer can be derived as follows: For the number to be even, its last digit must be 0, 2, 4, 6, or 8, for a total of 5 choices. The remainder of the answer depends on whether numbers that begin with 0, 00, or 000 are allowed. If such initial zeroes are not allowed, there are 9 choices for the first digit. Any of the ten digits may be used for the two remaining digits. Therefore the number of instances is 9 X 102 X 5 = 4500. If initial zeroes are allowed, the number of instances is 5000.
Wiki User
∙ 12y ago
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6*6*3 = 108 numbers.
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If a digit can be repeated there are 5 x 5 x 5 = 125 possible numbers If a digit cannot be repeated there are 5 x 4 x 3 = 60 possible numbers.
