Let's try and figure this one out...
First case (the easy one) - We want to use any of the 10 digits to create a 5-digit number. In this case, we have 5 slots and in each slot we can put any of 10 digits.
So the answer is 10*10*10*10*10 = 510 = 100,000 combinations
Second case - We want to create a 5-digit number using any of the 10 digits, but we only want to use each digit once. This turns out to be only a little more difficult.
Let's look at each digit individually.
First digit - We can use any digit from [0-9], so we have 10 possibilities.
Second digit - We can use any digit from [0-9] except for the one used in the first digit, so we now have 9 possibilities.
Third digit - We can use any digit from [0-9] except for the ones used in the first and second digits, so we now have 8 possibilities.
Fourth digit - As above, except we now have 7 possible choices.
Fifth digit - As above, except we now have 6 possible choices.
So our final number of combinations is 10 * 9 * 8 * 7 * 6 = 30,240 combinations
Special case - What happens if we want to create a number which does not begin with a zero? Well, we can make a simple adjustment to either of the above cases to take care of this. Just observe that the first digit is not limited to 9 possibilities [1-9], not 10.
Special first case = 9 * 10 * 10 * 10 * 10 = 90,000 combinations
Special second case = 9 * 9 * 8 * 7 * 6 = 27,216 combinations
6
Only one.
10
The answer is 10C3 = 10*9*8/(3*2*1) = 120 combinations.
Six combinations: 123, 132, 213, 231, 312, 321
10,000.
45
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
6
For reasons that should be obvious, there are 100,000 possible combinations of five digits if no restrictions are made on what the digits can be or how many times a digit may appear.(Okay, yes, it should be obvious, but: 00001 to 99999 is, trivially, 99999 combinations, and adding 00000 as well gives an even hundred thousand possibilities.)
five
45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.
Only one.
Assuming no duplication or repetition, 720
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
10