If order matters and a number cannot be repeated, then there are 16x15x14x13 = 43680 different combinations. If order does not matter then you must divide by the number of ways you can rearrage the same 4 numbers i.e. divide by 4x3x2x1=24 so you can select 4 numbers from a group of 16 in 43680/24 = 1820 ways.
In mathematical terms there are 43680 permutations of 16 numbers taken 4 at a time and 1820 combinations of 16 number taken 4 at a time.
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
Assuming that "number" means digits and that it is permutations (rather than combinations) that are required, the answer is 816 which is 281.475 trillion (approx).
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
600600 First, find how many different combinations of men can there be, which is 330; and how many different combinations of women can there be, which is 1820. Then, multiply them together and you get 600600
16 of them.
16
16 x 15 / 2 ie 120
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
16 i think
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are many combinations of two numbers that add up to 36. One combination is 20 + 16
16, in four sets of four. Plus expiry dates, and security numbers at the back.
Add up all the numbers and then divide by how many numbers there are... *Example* -8, -1, 9, 16 -8 + -1= -9+9= 0+ 16=16 16 divided by four(there are four numbers) THe mean is 4!
Assuming that "number" means digits and that it is permutations (rather than combinations) that are required, the answer is 816 which is 281.475 trillion (approx).
They are worth 16. There are four different combinations of 5-5-5 and four combinations of J-5. Eight combinations, each worth 2.
There are 18C4 = 18!/[18-4)!4!] = 18*17*16*15/(4*3*2*1) = 3060 combinations.
24 = 16