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ten factorial = 10! = 3,628,800
In a 2 x 2 factorial ANOVA, there are three null hypotheses tested. These include one for each of the two main effects (one for each factor) and one for the interaction effect between the two factors. Therefore, you test the null hypothesis that each factor has no effect on the dependent variable, as well as the null hypothesis that there is no interaction between the factors.
The number of permutations of the letter ABCDEF is 6 factorial, or 720.
There are 4! or factorial(4) = 24 ways.
3,628,800
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
1,2,3,4,5
When a disease is said to have a multi-factorial basis it means that there are many factors, both genetic and environmental, contribute to the disease.
ten factorial = 10! = 3,628,800
factorial
10! (read ten factorial)
There are 75600 permutations.
Ten of them.
Ten.
Ten.
18 factorial is equal to 6402373705728000 - with three consecutive zeroes at the end.
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