0
1,3,5,7,9,11,13,15,17,19,31,33,35,37,39,51,53,55,57,59,71,73,75,77,079,
91,93,95,97,99,111,113,115,117,119,131,133,135,137,139,151,153,155,
157,159,171,173,175,177,179,191,193,195,197,199,311,313,315,317,319,
331,333,335,337,339,351,353,355,357,359,371,373,375,377,379,391,393,
395,397,399,511,513,515,517,519,531,533,535,537,539,551,553,555,557,
0559,571,573,575,579,591,593,595,597,599,711,713,715,717,719,731,733,
735,737,739,751,753,755,757,759,771,773,775,777,779,791,793,795,797,
799,911,913,915,917,919,931,933,935,937,939,951,953,955,957,959,971,
973,975,977,979,991,993,995,997,999
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How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?
-4
How many strings of 3 decimal digits do not contain the same 3 digits?
How many strings of three digits are there? 000 to 999, or a total of 1000. How many strings of three digits contain the same three digits? That's 000, 111, 222 ... 999! ten in total. The difference is your answer: 1000-10 = 990.
How many 4 digit numbers can be formed from the digits 7341 if none of the digits can be repeated?
24
How many 3 digit numbers can be formed?
It depends upon whether the numbers can be used more than once. If the numbers can be used more than once, then there are 1,000 possible combinations; if not, then there are 720 possible combinations. ========== Assuming you are talking about integers you can calculate it this way: you can have any one of 9 digits for the first digit (zero is excluded because that would make it only a 2 digit number) You can have any one of 10 digits for the second and any one of 10 digits for the third digit. That gives you 9x10x10 = 900 different combinations for 3 digit numbers (not 1000). If you can include both negative and positive numbers as different numbers you get twice as many (2x900=18000). If you can count decimal numbers as 3 digit numbers (i.e. not restricted to integers) you can have 900 integers, 900 with the form xx.x, 1000 with the form x.xx (if zero is permitted to be the first digit and count as one of the 3 digits) or 900 (if a leading zero is NOT counted as one of the 3 digits). If a leading zero is NOT counted as one of the 3 digits, you could also have 1000 numbers of the form 0.xxx or just .xxx
How many counting numbers have four distinct nonzero digits such that the sum of the four digits is 10?
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
