13
Oh, dude, let me break it down for you. So, you've got 5 digits to choose from for the hundreds place, then 4 left for the tens place after you've used one for the hundreds, and finally 3 left for the units place after using 2 for the hundreds and tens. Multiply those together and you get 60 possible 3-digit numbers. Easy peasy, lemon squeezy!
30
If you are talking about 6 to the power of 30, then the answer is 6.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
that is not even close to a question 6 occures in first 30 numbers for just 1 time so probabability of 6 in 30 numbers= 1/30
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
29 of them.
There are 300.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
To find the two-digit counting numbers less than 30, we consider the numbers from 10 to 29, which gives us 20 two-digit numbers. The multiples of 20 that are two-digit numbers are 20. Since 20 is already included in the count of two-digit numbers less than 30, the total remains 20. Therefore, there are 20 two-digit counting numbers that are either less than 30 or a multiple of 20.
30
30
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
The numbers from 1 to 39 include both single-digit and double-digit numbers. There are 9 single-digit numbers (1 to 9) and 30 double-digit numbers (10 to 39). Therefore, the total number of digits is 9 (from single-digit numbers) + 60 (from double-digit numbers, as each has 2 digits) = 69 digits in total.
30
30 of them.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.