30
If you are talking about 6 to the power of 30, then the answer is 6.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
that is not even close to a question 6 occures in first 30 numbers for just 1 time so probabability of 6 in 30 numbers= 1/30
20, 40, 50
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
There are 300.
29 of them.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
30
30
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
30
30 of them.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
300600900are some
The digit zeroes appear in the numbers 10, 20, 30, 40 and 50, making a total of 5 digit zeroes.