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Oh, dude, let me break it down for you. So, you've got 5 digits to choose from for the hundreds place, then 4 left for the tens place after you've used one for the hundreds, and finally 3 left for the units place after using 2 for the hundreds and tens. Multiply those together and you get 60 possible 3-digit numbers. Easy peasy, lemon squeezy!
30
If you are talking about 6 to the power of 30, then the answer is 6.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
that is not even close to a question 6 occures in first 30 numbers for just 1 time so probabability of 6 in 30 numbers= 1/30