13
Go tmis
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4
60
10
10
30
If you are talking about 6 to the power of 30, then the answer is 6.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
that is not even close to a question 6 occures in first 30 numbers for just 1 time so probabability of 6 in 30 numbers= 1/30
20, 40, 50
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
There are 30 such numbers.
29 of them.
There are 300.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
30
30
30
30 of them.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
300600900are some
The digit zeroes appear in the numbers 10, 20, 30, 40 and 50, making a total of 5 digit zeroes.