0
This answer is based on assumptions that indicate we want the size of a set S of numbers, the five smallest of which are 1,111,111
1,111,112
1,111,114
1,111,117
1,111,121
and the two largest of which are 7,777,774
7,777,777
The following two numbers would therefore not be in S: 1
777,777 The answer is: 47 = (4x4x4x4x4x4x4) = 16,384
What else can I help you with?
HOW MANY five digit numbers are there with distinct digits?
First digit can be any of nine (not "0"), second can also be any of nine, third any of eight, fourth any of seven and fifth any of six, that is 9 x 9 x 8 x 7 x 6 = 27216 such numbers.
The probability that a number selected from random between 100 and 999 both inclusive will not contatin the digit 7?
For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.
What is the value of the digit 7 in the number 18.79?
The digit 7 is in the tenths place, therefore its value is 7/10 (or seven tenths).
What is the probability that a seven-digit phone number contains the number 7?
Best way to answer this question is by figuring out the probability of a phone number not containing the number 7. There are 9 other numbers that are not a 7, so odds of each digit not being a 7 is 90%. For a 7-digit number, calculation would be 0.9*0.9*0.9*0.9*0.9*0.9*0.9 or 0.9^7. This equals 47.8%, which means the odds of a phone number containing at least one 7 is 100% - 47.8%, which is 52.2%. But phone numbers do not begin with 0 or 1, so if we account for that, the odds of the first digit not being a 7 is 7/8, not 9/10. We replace the first 0.9 with 0.875, and the result is 53.5%. There are other scenarios we can take out, like numbers that begin with 555, but I'll just leave it at that.
Try to put the numbers 1 to 7 in the seven diamonds below so that the numbers in each row of three diamonds add up to 10 Each number can be used only once?
There are no seven diamonds below.
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
How many 3 digit numbers are formed using the digits 164?
seven which are 146 164 416 461 614 641
What is the digit of seven numbers?
1 million 1,000,000
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
What 3 digit numbers have one to seven as factors?
420 and 840
What were the typical formats of 1940s phone numbers and how did they differ from modern phone numbers?
In the 1940s, phone numbers typically consisted of a three-digit area code followed by a seven-digit local number, such as "ABC-1234." This format differed from modern phone numbers, which generally have a three-digit area code followed by a seven-digit local number, such as "(123) 456-7890."
What years were 4 digit phone numbers use in the us?
Four-digit phone numbers were primarily used in the United States before the widespread adoption of area codes and seven-digit dialing. This system was prevalent from the early 20th century until the late 1950s, when the North American Numbering Plan was introduced, requiring the use of three-digit area codes and seven-digit local numbers. The transition to seven-digit dialing became standard as more telephone lines were added and the need for more numbers grew.
How many 3 digit numbers are there that contain at least 1 seven?
252
How many numbers between 100 and 300 have a digit sum of 4?
Seven of them.
How many binary numbers can be written using seven digits?
A binary number consists of two possible digits: 0 and 1. When using seven digits, each digit can independently be either 0 or 1. Therefore, the total number of binary numbers that can be formed with seven digits is (2^7), which equals 128. Thus, there are 128 different binary numbers that can be written using seven digits.
How many different telephone numbers can be formed from a seven digit number if the first and last digit cannot be zero?
The number of possibilities is 9 x 10 x 10 x 10 x 10 x 10 x 9 = 8,100,000.
How many 7-digit numbers can be formed using the digits 1 2 3 4 and 8?
To form a 7-digit number using the digits 1, 2, 3, 4, and 8, we can use any of the five digits for each of the seven positions. Since repetition of digits is allowed, the total number of 7-digit numbers is calculated as (5^7). Thus, (5^7 = 78125). Therefore, there are 78,125 possible 7-digit numbers.
