There are no seven diamonds below.
For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.
The mean of those seven numbers is (5 + 9 + 6 + 6 + 11 + 8 + 4)/7 = 7 The median of those seven numbers is 6. The mode of those numbers - the only number which appears more than once - is 6.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
There are seven positions: _ _ _ _ _ _ _ Each must be filled by number 0-9 and numbers can be repeated. The first three positions must be 2,4,5, therefore, 2 4 5 _ _ _ _ For the other for positions, the 4th and 7th position cannot be 0 (therefore only 9 possibilities: 1-9) and the 5th and 6th position can be any number (10 possibilities: 0-9). Therefore, the total number of possibilities is 9 * 10 * 10 * 9 = 8100 since the positions are independent.
Hopefully not being too obvious here, I have been frustrated (after searching each of seven home dictionaries, crosswordbooks, "word finders", etc., etc,....) I'll just say the following. Anyone who wishes to correct me, does so at no peril of my wrath: Unfactorable numbers are known as Prime Numbers. OK? Thanks for comments--- Mr. C. well a unfactorable number is, to use the prefix meaning, a number that can't be factorised or doesn't have any factors and nosuch number exists as 0=any number times by 0, and 1=1 times itself. both numbers above have been said to not fit into either the prime of composite number groups
First Row 7,6 Second row 4,1,5 Third row 3,2
Yes seven is a prime number and the only numbers that will go in to seven is one and seven.
you whole numbers that seven go in to
There is an infinite number of numbers that are not divisible by seven!
number of prime numbers which are in the seven times tables: 1 prime numbers are in the seven times tables: 7 only
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
Yes.
7/8 is a rational number because rational numbers are fractions, numbers that terminate, numbers that repeat.
Mixed numbers can't be whole numbers.
there are seven numbers in the number
510510
you replace all the numbers below the 10 place-value with 0 example: 2678 since eight is in the 5+ category, when you replace with zero, you make the seven one number higher. if not, you keep the seven as it is.