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How many ways are there to write a 3-digit positive integer using digits 1 3 5 7 and 9 if no digit is used more than once?
There are 5 choices for the first digit, as any of the 5 given digits can be used. After selecting the first digit, there are 4 remaining choices for the second digit, and 3 choices for the third digit. Therefore, the total number of ways to write a 3-digit positive integer using the given digits without repetition is 5 x 4 x 3 = 60 ways.
How many 4 digit numbers can be made by he digits 0123 using the digit once?
2
How many even four digit numbers can be made using 02356 where the first digit is cannot be 0 and no digits are repeated?
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
Using four different digits what is the least sum you can get when you add two digit numbers?
2222
How may ways are there to write 3 digit positive integer using 123456789 digits?
9*9*9 = 729 ways.
How many ways are there to write a 3-digit positive integer using digits 1 3 5 7 and 9 if no digit is used more than once?
There are 5 choices for the first digit, as any of the 5 given digits can be used. After selecting the first digit, there are 4 remaining choices for the second digit, and 3 choices for the third digit. Therefore, the total number of ways to write a 3-digit positive integer using the given digits without repetition is 5 x 4 x 3 = 60 ways.
How do you select digits in an integer in java?
In Java, you can select digits from an integer by converting it to a string using String.valueOf(int), which allows you to access individual digits via their indices. For example, if you have an integer num, you can do String strNum = String.valueOf(num); and then access digits using strNum.charAt(index). Alternatively, you can use arithmetic operations, such as dividing and taking the modulus, to extract digits. For instance, to get the last digit, you can use num % 10, and to remove the last digit, you can use num / 10.
How many odd 3 digit positive integers can be written using the digits 2 3 4 5 and 6?
To form a 3-digit odd positive integer using the digits 2, 3, 4, 5, and 6, the last digit must be an odd number. The available odd digits are 3 and 5. If we choose 3 as the last digit, we can use any of the remaining digits (2, 4, 5, 6) for the first two digits, giving us 4 options for the first digit and 4 options for the second digit (since we can repeat digits). This results in (4 \times 4 = 16) combinations. Similarly, if we choose 5 as the last digit, we again have 4 options for the first digit and 4 for the second, resulting in another (4 \times 4 = 16) combinations. Thus, the total number of odd 3-digit integers is (16 + 16 = 32).
What is the smallest number you can make using the digits 5 7 3 and 1?
The smallest positive integer is 1357.
In java How do you have a method take in an int value and return an int containing sum of the individual digits in the number using a recursive method?
Add the last digit plus the sum of all the previous digits. The base case is that if your integer only has a single digit, just return the value of this digit. You can extract the last digit by taking the remainder of a division by 10 (number % 10), and the remaining digits by doing an integer division by 10.
How do you write a visual basic program to sum the odd number digits of a 12 digit code using division and Mod and while loops?
Function sum_odd_digits(ByVal number As Integer) As Integer Dim digit As Integer sum_odd_digits = 0 While number <> 0 digit = number Mod 10 If digit And 1 Then sum_odd_digits = sum_odd_digits + digit number = number / 10 End While End Function
How many odd 3 digit positive integers can be written using the digits 2 and 3 and 4 and 5 and 6?
Fifty
What is the greatest seven-digit number using four different digits?
9,999,876 is the greatest seven-digit number using four different digits.
Have 1 of each of these digits 1p 2p 5p 10p 20p how many sums can you make using these digits?
10p is not a digit. A digit is an integer in the range 0-9. Leaving that aside, you can make 31 sums from the 5 coins. If you allow 0 as a valid sum, the answer is 32.
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
What is the smallest 6-digit number having different digits?
It is -987654. The smallest POSITIVE number is 102345.
