count the number of times you get number 1, when you roll a pair of dice.. cheerio
3 ways 6 and 1. 3 and 4. 5 and 2.
there is a probability of 1/6.Answer:For two dice to show 5 and 2:There are two ways to roll a "good" number (2 or 5) for the first dice. This gives odds of 2/6.For the second dice there is one way to role a good number ( 1 in 6)The odds to roll both a 2 and a 5 are (2/6)x(1/6) or 2/36 or 1/18.
We need to find two things. FIrst we need to know how many ways there are to roll a 3 and second we need to look at how many total events (the sample space) there are. So we could get a 3 with a 1 and 2 or a 2 and 1. Since we are rolling 2 dice we can't have 3 and 0 since we cant roll a 0. So there are 2 ways to get 3. Now Each die has 6 different outcomes when we roll it so using the multiplication law, we hae 36 possible outcomes. Of these 2 give us a sum of 3 so that is 2/36 or 1/18
There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.
The probability is 1 in 36
count the number of times you get number 1, when you roll a pair of dice.. cheerio
3 ways 6 and 1. 3 and 4. 5 and 2.
12
6
if you are talking about getting a roll that totals 6 - there is only one way to roll that - get all ones. as such there are 6^6 -1 = 46656 -1 = 46655 other ways to roll the dice. so the odds of not rolling a total of 6 with 6 dice is 46655/46656 = .~99.997857%. If you are talking about not rolling a 6 on ANY of the dice, there are 5 ways to roll each die that will give you something other than 6 so the number of ways to not roll any 6's is 5^6 = 15625. That means the odds of not rolling any 6's on 6 dice is 15625/46656 = ~38.489798%
That's a very nice problem !Total number of possible outcomes with two dice = 36.Factors of twelve = 1, 2, 3, 4, 6, and 12.Number of ways to roll a '1' = zeroNumber of ways to roll a 2 = 1 . .. . (snake-eyes)Number of ways to roll 3 = 2 . . . . . (1,2 and 2,1)Number of ways to roll 4 = 3 . . . . . (1,3 / 2,2 and 3/1)Number of ways to roll 6 = 5 . . . . . (1,5 / 2,4 / 3,3 / 4,2 and 5,1)Number of ways to roll 12 = 1 . . . . (box-cars)Total number of successful rolls = 12Probability = 12/36 = 1/3 = 33 and 1/3 percent.
1/9 ways. total sample space for the experiment is 36(because you have two dice). and you can get 5 in 4 ways that is (1,4),(4,1),(2,3),(3,2). hence 4/36= 1/9.
There are 36 possible outcomes when we roll a pair of dice. Rolling a five can be done the following ways: 3-2, 4-1, 2-3 and 1-4. That's four ways to roll a five with one roll of the dice. The odds of rolling a five are 4 in 36, or 1 in 9. That makes the probability of rolling a five equal to 0.11111....We know that the probability of something is a ratio of the number of times it can be done to the total number of things that are possible. Probabilities range from zero to one, inclusive. If something has a probability of zero, it cannot happen. Like rolling a 13. A 13 cannot be rolled with one roll of a pair of standard dice. Thus the probability of rolling a 13 is zero, as it cannot happen.If something has a probability of one, it must happen. Like the probability of rolling an odd or an even number with one roll of a pair of dice. Since any number we roll must be either odd or even, then the probability of rolling an odd or an even number with one roll of a pair of dice is one. An odd or an even number must turn up, and that is why the probability of rolling an odd or an even number with one roll of the dice is one. Lastly, we've seen that the probability of rolling a given number with one roll of the dice is the number of times that number might appear divided by the total number of possibilities that might appear.
The are more ways to roll a 6 (five ways) than to roll a 4 (three ways).
6 ways: 1 and 4, 4 and 1, 2 and 3, 3 and 2, 5 and 0, 0 and 5 A five can be rolled with either dice being a 2,3,4,1 and the other dice being the correlating number that adds to five ie. 4-1, 1-4. 3-2. 2-3. There is no 0 on a die.
Oh, dude, let me break it down for you. So, to get a sum of 12 with three dice, you can roll a 6, a 5, and a 1. Or, you could roll a 5, a 6, and a 1. Or a 4, a 4, and a 4. That's like... three ways. Math can be fun, right?