We need to find two things. FIrst we need to know how many ways there are to roll a 3 and second we need to look at how many total events (the sample space) there are. So we could get a 3 with a 1 and 2 or a 2 and 1. Since we are rolling 2 dice we can't have 3 and 0 since we cant roll a 0. So there are 2 ways to get 3. Now Each die has 6 different outcomes when we roll it so using the multiplication law, we hae 36 possible outcomes. Of these 2 give us a sum of 3 so that is 2/36 or 1/18
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
With one roll of three dice, the probability is 7/8.
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
The probability is 90/216 = 5/12
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
The probability is 7/36.
uummm!!!! The probability would maybe close to 5 or 4. * * * * * The answer is clearly incorrect because the probability of an event cannot be greater than 1. The actual probability, assuming the dice are fair, is 4/36 = 1/9 = 11.11...%
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
If they are normal dice, the probability is 0.
With one roll of three dice, the probability is 7/8.
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
The probability is 90/216 = 5/12
The probability of the event is 25/36.
With standard dice, zero.
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
If using regular dice, the probability is 0 since the minimum sum from four dice is 4.