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The only three-digit number that fits the criteria of being a square number and having a product of its digits equal to two is 128. This is because 128 is a square number (11^2 = 121, 12^2 = 144) and the product of its digits (1 x 2 x 8) equals 16, which is not equal to two. Therefore, there is no three-digit number that meets all the given conditions.
The numerator of the product is the product of the three numerators and the denominator of the product is the product of the three denominators.So, for example, (a/b)*(c/d)*(e/f) = (a*c*e)/(b*d*f)
The number of strings of four decimal digits that have exactly three digits which are nine is the number of ways to choose three places to choose the nines multiplied by the number of possibilities for the other digits (because you can put all of the possibilities in an array so that each column has a different way of arranging the nines and that each row has a different set of other digits (because they do not affect each other)). The number of ways to choose the three places to choose the nines is the same as the number of ways of choosing 4-3=1 spot for there not to be a nine. The number of ways of choosing 1 spot where there are 4 spots is 4 (the first, the second, the third, or the fourth). Since there are 9 digits that are not nine, the number of choices for the other digits is 9 (since there is only one digit). Thus, there are 4*9=36 strings of four decimal digits that have exactly three digits which are nine.
Just six numbers... 345, 354, 435, 453, 534 & 543
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
Just multiply one pair of your numbers to give you a product, and then multiply their product by your third number.
It can have one . . . 1.0 x 1.0 = 1 It can have two . . . 1.0 x 0.1 = 0.1 It can have three . . . 10 x 10 = 100 It can have four . . . 99 x 99 = 9801 and .01 x .01 = .0001
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Ignore the decimal points and multiply the numbers to give the product: 308*29 = 8932Count the number of digits AFTER the decimal points in the two numbers. Two in the first and one in the second, making three in all.That is the number of digits after the decimal point that you want in the answer. So insert the decimal point that many digits from the end of the product.Thus 8932 becomes 8.932Done!
You get 3 quarters of a number by multiplying the number by .75; or you can multiply it by .25 and then multiply the product by 3. Or, you can multiply the number by 3, and then divide the product by 4.Half it and half it again. Then times it by 3
When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 × 20 = 6200 6200 already has two significant digits.
1. find the product of the first two 2. multiply that product with the third number
Because if you multiply a negative number three times, the product will be negative.
The only three-digit number that fits the criteria of being a square number and having a product of its digits equal to two is 128. This is because 128 is a square number (11^2 = 121, 12^2 = 144) and the product of its digits (1 x 2 x 8) equals 16, which is not equal to two. Therefore, there is no three-digit number that meets all the given conditions.
Four. (100 x 10 = 1,000)
Multiplying a 2-digit number by a 1-digit number involves multiplying the digits in the ones and tens place and then adding the products. Similarly, multiplying a 3-digit number by a 1-digit number follows the same principle, where you multiply the digits in the ones, tens, and hundreds place and then add the products. The main difference is that in the latter case, you are dealing with three sets of digits to multiply and add, whereas in the former, you only have two sets of digits.
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