There are an unlimited number of possibilities. If you need five consecutive whole numbers, that's different, your answer would b e 51, 52, 53, 54, and 55.
6 numbers can go into 20; they are 1, 2, 4, 5, 10 and 20.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
Oh, dude, there are like 9,000 four-digit numbers. It's simple math, you just start from 1000 and go up to 9999. So, if you ever need to count them all, just grab some snacks and get comfy because you'll be here for a while.
In Oz Lotto, players need to select 7 numbers from a pool of 1 to 45 numbers to win the jackpot. The winning numbers are drawn randomly, and if a player's chosen numbers match all 7 drawn numbers, they win the jackpot prize. Matching fewer numbers can also result in winning lower-tier prizes.
If you have an odd amount of numbers than there is no problem but say if you had 8 numbers you take the 4th and 5th numbers and find the average of the two. here is an example 1,3,4,5,7,9,11,14 you average 5 and 7,the 4th and 5th numbers, so the average is 6.hope this helped :)
1 and 53
Two: 1 and 53.
53 and 2 are both prime numbers and their LCM is 106
None, 53 is a prime number.
Only 1 and 53 ... it's a prime number
1, 2, 53, 106.
53/100 is in SF. Can you divide both numbers by 2? No. (2 cannot go into 53)
Since 53 is a prime number, its only prime factor is itself.
1 and 53. 1 x 53 = 53 There are no other whole number solutions as 53 is a prime number.
The only such number is 1.
These numbers: 1, 2, 4, 53, 106, 212.
1, 2, 4, 53, 106, 212.