There are an unlimited number of possibilities. If you need five consecutive whole numbers, that's different, your answer would b e 51, 52, 53, 54, and 55.
6 numbers can go into 20; they are 1, 2, 4, 5, 10 and 20.
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
If you count 0000 to 9999 you have 10,000. For whole numbers you have 9999. * * * * * Not sure about "whole" numbers. There are 10,000 in all, of which 9000 (from 1000 to 9999) do not have leading 0s.
In OZ Lotto numbers are drawn from a machine containing 45 balls, numbered from 1 to 45 inclusive. For a standard game, you choose 7 numbers from this range.OZ Lotto offers 7 'divisions' or levels of prizes.Here is what you need to match in one game to win a prize:Division 1: All 7 main winning numbersDivision 2: Any 6 main winning numbers and either supplementary numberDivision 3: Any 6 main winning numbersDivision 4: Any 5 main winning numbers and either supplementary numberDivision 5: Any 5 main winning numbersDivision 6: Any 4 main winning numbersDivision 7: Any 3 main winning numbers and either supplementary numberTo find out the Oz Lotto numbers and the actual prize money for each division each week go to the Oz Lotto results at OzLotteries - link below.
If you have an odd amount of numbers than there is no problem but say if you had 8 numbers you take the 4th and 5th numbers and find the average of the two. here is an example 1,3,4,5,7,9,11,14 you average 5 and 7,the 4th and 5th numbers, so the average is 6.hope this helped :)
1 and 53
Two: 1 and 53.
53 and 2 are both prime numbers and their LCM is 106
None, 53 is a prime number.
Only 1 and 53 ... it's a prime number
53/100 is in SF. Can you divide both numbers by 2? No. (2 cannot go into 53)
1, 2, 53, 106.
1 and 53. 1 x 53 = 53 There are no other whole number solutions as 53 is a prime number.
Since 53 is a prime number, its only prime factor is itself.
The only such number is 1.
These numbers: 1, 2, 4, 53, 106, 212.
1, 2, 4, 53, 106, 212.