Let M be the mean.
P( X > 5.52) =0.1271
Standardize X by subtracting the mean and dividing by the standard deviation.
z = (52.2-M) /4
From the normal distribution tables, P( z > 1.14 )=0.1271
Therefore, (52.2-M) / 4 = 1.14
Solve for M, the mean.
52.2-M = 4(1.14) = 4.56
M=52.2-4.56 =47.64
Approx 0.0027
30 percent.
The mean is 0.9592
a mean of 1 and any standard deviation
probability is 43.3%
It is the Standard normal variable.
with mean of and standard deviation of 1.
Approx 0.0027
with mean and standard deviation . Once standardized, , the test statistic follows Standard Normal Probability Distribution.
30 percent.
3
The mean is 0.9592
a mean of 1 and any standard deviation
It is 0.5
I have included two links. A normal random variable is a random variable whose associated probability distribution is the normal probability distribution. By definition, a random variable has to have an associated distribution. The normal distribution (probability density function) is defined by a mathematical formula with a mean and standard deviation as parameters. The normal distribution is ofter called a bell-shaped curve, because of its symmetrical shape. It is not the only symmetrical distribution. The two links should provide more information beyond this simple definition.
probability is 43.3%
a is true.