There are 40320 ways.
7*6*5*4*3*2*1= 5040 different ways
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
30 ways.
Consider one placement at a time. The first book on the shelf could be any of seven. The second could be any of the remaining six. This continues with the rest. The total combinations are: 7! = 7*6*5*4*3*2*1 = 5040
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
7*6*5*4*3*2*1= 5040 different ways
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5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
30 ways.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
8!=8*7*6*5*4*3*2*1=40320 ways
The answer to this one is 24. You can do this mathematically by 4*3*2*1.
because of gravity. i think
Consider one placement at a time. The first book on the shelf could be any of seven. The second could be any of the remaining six. This continues with the rest. The total combinations are: 7! = 7*6*5*4*3*2*1 = 5040
The number of permutations of 7 things taken 7 at a time is 7 factorial, or 5040.
There are many different possible lengths for a closet shelf. There is no set or standard length for a closet shelf.
Answerthe answer is 24 WHICH is the result of the multiplication: 4x 3 x 2 x 1 = 24. You can try it practically as: Numbering books as A,B, C, and D then the variations are:ABCDABDCBACDBADCCDABCDBADCABDCBABCADBCDACBADCBDAADBCADCBDABCDACBBDACBDCADBACDBCAACBDACDBCABDCADB