Once you have picked the first ball, you will have five left to pick from, one of which will be the same color as the first pick, and four of colors that you don't want. The probability of picking the second ball of the same color is then 1/5 or 0.20. P.S. It really isn't fair to have someone else do your homework for you.
0.8.
If the balls are selected at random, then the probability is 12/95.
It is 1/7 if a ball is selected at random.
11/18 x 10/17 = .359
If I have 3 red balls 3green balls 2 white balls & 5black all in one sack what is the probability of finding a white ball?
0.8.
Probability can be expressed as a ratio, a fraction, or a decimal. For example if there are 4 red balls and 4 white balls in a bucket and you pick one without looking the probability (chance) that you will pick a red ball is a half, because half the balls are that colour. You can say that the probability of that happening is 1/2 or 50% or 0.5 The probability is the same for choosing a white ball. * * * * * There is a fourth way, and that is in the form of odds.
6/10 or reduced is 3/5
If the balls are selected at random, then the probability is 12/95.
The probability is (6/14)*(5/13) = 30/182 = 0.1648 approx.
The probability the first ball will be red is 5/8. The probability that the first and second balls will be red is 5/8 x 4/7. The probability that the first, second, and third balls will be red is 5/8 x 4/7 x 3/6, or overall 60/336 (about 17.86%).
The probability of getting 3 white balls in a draw of 5 balls with replacement from an urn containing white balls and black balls is always greater than the same test without replacement, because the number of white balls decreases when you draw a white ball and do not replace it. The ratio of white to black with replacement is constant, and is always less than one, assuming there is at least one black ball. The ratio of white to black without replacement decreases each turn, and is still less than one, and is less than the previous ratio, unless the question asked about 2 white balls or less.
If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.
2/7 = 28.57%
It is 1/7 if a ball is selected at random.
The question cannot be answered because it is incomplete and a complete version cannot be found.
11/18 x 10/17 = .359