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What else can I help you with?
What 4 digit numbers when combined look the same upside down?
1, 5, 8, and 0.
How many 3 digit numbers are multiples of 5?
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
How many 3 digit numbers can be formed from the digits 24578 if no digits can be repeated?
Oh, dude, let me break it down for you. So, you've got 5 digits to choose from for the hundreds place, then 4 left for the tens place after you've used one for the hundreds, and finally 3 left for the units place after using 2 for the hundreds and tens. Multiply those together and you get 60 possible 3-digit numbers. Easy peasy, lemon squeezy!
How many 4 digit combinations can be made with numbers 3 7 9 4?
The number of combinations possible for taking a specified sub-set of numbers, r, from a set, n, isC(n,r) = n!/[r!(n-r)!]In this case, n = 4 and r = 1, soC(n,r) = 4!/1!3!C(n,r) = 24/6C(n,r) = 4Therefore, there are four possible combinations of the numbers 3, 7, 9 and 4.==================================This contributor strongly disagrees, but is leaving the original answer hereso that others can shop and compare.With their commas, parentheses, and factorials, the formulas are certainly impressive.Only the conclusion is wrong.The question specified "4-digit" combinations, so 'n' and 'r' are both 4.Now, to come down off the pedestal and make it understandable as well asformally rigorous ..."Combination" really means different groups of 4 digits that you can select outof the four you gave us. There's only one of those groups.If you actually want to know how many different 4-digit numbers you can makefrom them, then what you want is called "permutations" of the four digits, andyou can think of it this way, without using 'n', 'r', or parentheses or factorials:The first digit can be any one of 4. For each of those . . .The second digit can be any one of the remaining 3. For each of those . . .The third digit can be either one of the remaining 2.So the total number of different ways to line them up is (4 x 3 x 2) = 24 different 4-digit numbers.
How do you round 534307164 to the nearest 10 million?
You look at the digit in the one millions position, which is a 4. That causes the number to be rounded down to 530000000.
If you write down all the numbers from 1 to 100 how many times will you write the digit 3?
The digit 3 will be written 20 times.
How many times will the digit 7 appear if you write down the natural numbers from 1 to 100?
18 times
How many times does 4 occur at tense place if we write down all the two digit numbers?
10
If you write down all the numbers from 1 to 100 how many times will you write the digit 9?
20, don't forget 90, 91, 92, 93 ...... etc
What are the steps for dividing multi-digit numbers?
To divide multi-digit numbers, start by determining how many times the divisor can fit into the leading digits of the dividend. Write that number above the dividend as part of the quotient. Multiply the divisor by this quotient and subtract the result from the leading digits of the dividend. Bring down the next digit from the dividend and repeat the process until all digits have been brought down, yielding the final quotient and remainder if applicable.
How many times is the digit 3 printed n number from 1 to 11521?
To determine how many times the digit 3 appears in the numbers from 1 to 11,521, we can break it down by counting occurrences in each digit place (units, tens, hundreds, and thousands). A detailed analysis or programming solution can provide the exact count, but generally, it is estimated that the digit 3 appears approximately 4,000 times in that range, as it occurs regularly in various positions across the numbers. For precise results, one would typically write a program or use combinatorial counting methods.
How do you times big numbers?
Write the two sums down one below the other and then draw a line underneath like so, then just do it backwards. do 4x6 then write it below. If you get a double digit then write the 4 underneath the 6 and a small 2 underneath the 4 next to the 6. Then when you times the next line add it on to the total 2344 x 1946 --------
How do you multiply 2 digit numbers times 2 digit numbers?
You line them up and down and then multiply the first ones up and down on the right. then you do the diagonally ones and then you put a zero on the bottom right. then you go to the second number on the right and do the one diagonally and then the on up and down. then you add the two together and you have your answer. example:
If you write down all the numbers between 300 to 400 how many times will you write the digit 3?
118 The following from rjsiekman; Think of it as the number of times the 3 will be written in the hundreds, tens, and ones column. This analysis assumes whole numbers; otherwise you can write a 3 an infinite number of times. In the hundreds, 301.....399 is 99 (because it is stated the numbers between 300 & 400; 300 is not included). In the tens, 3 will be written for 330....339 which adds another 10. In the ones, 3 will be written for 303, 313....393 which adds another 10. So, in total, the 3 will be written 119 times.
How is multiplying by multi-digit numbers similar to multiplying by two-digit numbers?
Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
What if two numbers are the median?
Then you write down both numbers
How do you do long division with numbers 936 and 7?
To perform long division with 936 and 7, start by determining how many times 7 fits into the first digit of 936 (which is 9). Since 7 goes into 9 once, write 1 above the line. Subtract 7 from 9, leaving 2, then bring down the next digit (3), making it 23. Next, see how many times 7 fits into 23, which is 3 times (7 x 3 = 21). Write 3 above the line, subtract 21 from 23 to get 2, then bring down the last digit (6), making it 26. Finally, see how many times 7 fits into 26, which is 3 times (7 x 3 = 21), subtract to get 5, and since there are no more digits to bring down, the final result is 133 with a remainder of 5.
