Yes, unless the 3 digit number is negative, or a decimal.
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A number with more than one digits: that is, an integer greater than 9.
In the decimal place value system, each digit is ten times bigger than the digit on its right
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If you multiply your number by any number greater than 1, the result will be greater than the starting number - assuming your number is positive. If your number is negative, you need to multiply it by any number less than 1, to get a result that is greater than the original number. To get a number that is slightly greater, multiply by a number that is slightly greater than 1 (ot slightly lee than= -1).
There will be more than one answer. To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The lowest 3-digit number satisfying the condition is 107 (which is 9x12 - 1); the highest is 998 (which is 9x111 - 1). Some answers: 107 / 9 = 11 R8 125 / 9 = 13 R8 998 / 9 = 110 R8