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To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The lowest 3-digit number satisfying the condition is 107 (which is 9x12 - 1); the highest is 998 (which is 9x111 - 1). Some answers: 107 / 9 = 11 R8 125 / 9 = 13 R8 998 / 9 = 110 R8

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Related Questions

What three digit number divided with a single digit will result in a remainder of 0?

100


What three digit number divided with a single digit will result in a remainder of 3?

111


What three digit number divided with a single digit will result in a remainder of 4?

Probably many answers, but for example 100 / 8 = 96 remainder 4


What three digit number divided with a single digit will result in a remainder of 9?

That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.


When dividing a 3 digit number by a 1 digit number for what divisors can you get a remainder 8?

Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8


What is the remainder of 245 divided by 9?

27.2222


Does 4554 divided by 9 have a remander?

506


What is the remainder of 8 divided by 28772?

0.0003


Is 60 divisible by 8?

2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).


What is the largest number you can divide by a single-digit number and still get a single digit number with no remainder for an answer?

81 is.


What number can be divided by 6 without a remainder but when divided by 2 3 4 5 or 6 leaves 1?

Not possible ! No single number will match allof your criteria ! Additionally - you've used the number 6 twice in your question - bothconditions can't be true !


Is 646 divisible by 9?

6 + 4 + 6 = 16 1 + 6 = 7 → No; 646 is not divisible by 9 (there is a remainder of 7). ----------------------------------------- Only if the sum of the digits is divisible by 9 is the original number divisible by 9. Repeat the test on the sum until a single digit remains; only if this single digit is 9 is the original number divisible by 9, otherwise this single digit is the remainder when the original number is divided by 9.

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