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When the population standard deviation is not known the sampling distribution is a?

If the samples are drawn frm a normal population, when the population standard deviation is unknown and estimated by the sample standard deviation, the sampling distribution of the sample means follow a t-distribution.


As the sample size increases the standard deviation of the sampling distribution increases?

No.


What is the sampling distribution when the standard deviation is known?

When the standard deviation of a population is known, the sampling distribution of the sample mean will be normally distributed, regardless of the shape of the population distribution, due to the Central Limit Theorem. The mean of this sampling distribution will be equal to the population mean, while the standard deviation (known as the standard error) will be the population standard deviation divided by the square root of the sample size. This allows for the construction of confidence intervals and hypothesis testing using z-scores.


Why you need sampling distribution?

in order to calculate the mean of the sample's mean and also to calculate the standard deviation of the sample's


What name do you give to the standard deviation of the sampling distribution of sample means?

the central limit theorem


What is sampling distribution of the mean?

Thanks to the Central Limit Theorem, the sampling distribution of the mean is Gaussian (normal) whose mean is the population mean and whose standard deviation is the sample standard error.


We have a population with mean of 100 and standard deviation of 28 take repeated samples of size 49 and calculate the mean of each sample to form a sampling distribution Is it a Normal Distribution?

a) T or F The sampling distribution will be normal. Explain your answer. b) Find the mean and standard deviation of the sampling distribution. c) We pick one of our samples from the sampling distribution what is the probability that this sample has a mean that is greater than 109 ? Is this a usual or unusual event? these are the rest of the question.


How do you calculate Z and T scores?

z=(x-mean)/(standard deviation of population distribution/square root of sample size) T-score is for when you don't have pop. standard deviation and must use sample s.d. as a substitute. t=(x-mean)/(standard deviation of sampling distribution/square root of sample size)


How would the mean and standard deviation change if the largest data in each set were removed?

Yes. The standard deviation and mean would be less. How much less would depend on the sample size, the distribution that the sample was taken from (parent distribution) and the parameters of the parent distribution. The affect on the sampling distribution of the mean and standard deviation could easily be identified by Monte Carlo simulation.


Describe the sampling distribution model for the sample proportion by naming the model and telling its mean and standard deviation?

it is the test one tail


Which of the following is true regarding the sampling distribution of the mean for a large sample size?

It has the same shape, mean, and standard deviation as the population.


The standard error of the mean is the standard deviation of the sampling distribution of the sample mean?

a large number of samples of size 50 were selected at random from a normal population with mean and variance.The mean and standard error of the sampling distribution of the sample mean were obtain 2500 and 4 respectivly.Find the mean and varince of the population?

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