For exactly two; we take the chance that for the first two coins come out heads and the second 2 come out tails. and then we multiply by the number of different possibilities. (i.e it could be the first and third or the first and fourth). so we get .5*.5*.5*.5*6=.375=37.5%
if you want 2 or greater. the answer by similar logic is .5625 or 56.25%
1 chance in 4
There is a probability of 0.5 of heads on each coin, so there is a 1/2 * 1/2 *1/2 = 1/8 = 0.125 chance that all coins land heads. You can also express this as a percentage, 12.5% chance. The odds are 1 in 8 that this can happen.
2/9
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
The probability is 1/21/21/2*1/2=1/16, or 0.0625 or 6.25%
The probability of tossing two heads in two coins is 0.25.
Coins do not have numbers, there is only the probability of heads or tails.
If they are fair coins, it is 1/16.
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
(0.5)n
1 chance in 4
6/16 = 3/8
1/36
The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.
It is 1/2^7 = 1/128.
There is a probability of 0.5 of heads on each coin, so there is a 1/2 * 1/2 *1/2 = 1/8 = 0.125 chance that all coins land heads. You can also express this as a percentage, 12.5% chance. The odds are 1 in 8 that this can happen.
1/2