For exactly two; we take the chance that for the first two coins come out heads and the second 2 come out tails. and then we multiply by the number of different possibilities. (i.e it could be the first and third or the first and fourth). so we get .5*.5*.5*.5*6=.375=37.5%
if you want 2 or greater. the answer by similar logic is .5625 or 56.25%
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1 chance in 4
There is a probability of 0.5 of heads on each coin, so there is a 1/2 * 1/2 *1/2 = 1/8 = 0.125 chance that all coins land heads. You can also express this as a percentage, 12.5% chance. The odds are 1 in 8 that this can happen.
2/9
The probability is 1/21/21/2*1/2=1/16, or 0.0625 or 6.25%
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.