figure it out yourself or ask your mom
48 marbles
at least 39 blue marbles
12 blue marbles
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
24
1/8 of 56 is 7, so he has 49 marbles left.
They had altogether at first 176 marbles (Mar has 44 and Jay has 132).
20% of 50 marbles is 1 fifth of the marbles in the bag. so 50 marbles divided by 5 =10 blue marbles
1/8 of 56 is 7 since 7x8=56 So Tim lost 7 marbles.
23
120 marbles.30 is a fifth of 150; 30 x 5 = 150.
2
48 marbles
at least 39 blue marbles
96 - 25 - 13 + 67 - 14 - 8 = 103
There are at least 11 green marbles in the bag.
The probability of selecting 4 red marbles or 5 blue marbles depends on how many marbles there are altogether, and how many of the total number of marbles are red and how many are blue.