1. Divide 1035 in the ratio of 2:3:4.
2. A father wants to leave $4675 to his four children in the ratio of 1:3:3:4. How much will each of the four children receive?
3. John plans to donate his collection of 3042 books to three libraries in the ratio of 1:3:5. How many books will each library get?
To get the answer, divide the number representing the total, by the sum of the terms in the ratio then, multiply the quotient by each of the term in the ratio.
1. 1035 = number representing the total
2, 3 and 4 = terms in the ratio
9 = sum of the terms in the ratio
1035 / 9 = 115
then, multiply 115 by each of the term in the ratio
115 X 2 = 230
115 X 3 = 345
115 X 4 = 460
Final Answer = 230, 345 and 460
To check, add them all
230 + 345 + 460 = 1035
2. $4675 = total amount father wants to leave to the children
1, 3, 3 and 4 = terms in the ratio
11 = sum of the terms in the ratio
$4675 / 11 = $425
so, we need to multiply this by each of the term in the ratio
$425 x 1 = $425
$425 x 3 = $ 1275
$425 x 3 = $ 1275
$425 x 4 = $ 1700
Final Answer = $425, $1275, $1275 and $1700
To check,
$425 + $ 1275 + $ 1275 + $ 1700 = $ 4675
3. 3042 = total number of books
1, 3 and 5 = terms in the ratio
9 = sum of the terms in the ratio
3042 / 9 = 338
when multiplied by each term in the ratio, we get
338 x 1 = 338
338 x 3 = 1014
338 x 5 = 1690
Final Answer = 338, 1014 and 1690
to check
338 + 1014 + 1690 = 3042
There are many different problems and different ways for solving them.
A systematic sample is not something that you can solve!
Big M IS ONE OF THE METHOD USED TO SOLVE AN L.P PROBLEM
3x4-7x3+5x2-3x+6
P(A)=.35 P(B given A)=0.6 P(A and B)= ?
cost * (1 - discount % as a decimal)
just think it throw
unsaon ?
Ariana Grande
By doing the arithmetic.
3+8+13+18+...+58
In the same way that you would solve equations because equivalent expressions are in effect equations
By Trowing garbages
There are many problems involving factors and the question needs to be more specific.
Dahil sa tae.
You cannot solve proper fractions. You may be able to solve problems involving fractions but that is NOT the same thing. Furthermore, the solution methods depend on the problem.
Algebra is used to solve simple problems involving know and unknown variables.