Total number of outcomes = 6 x 6 x 6 = 216
Number of ways that are successful:
1 1 -
1 - 1
- 1 1
1 1 1
2 2 -
2 - 2
- 2 2
2 2 2
3 3 -
3 - 3
- 3 3
3 3 3
etc.
Four ways for each number 1 thru 6 = 24 possible successes. But for each of the one's with a dash (-), there are 5 outcomes (121, 131, 141, 151, 161, 211, 311,411,...etc), so the real number of ways for this to happen is 16 ways for each number: 6 x 16 = 96.
Probability of success = 96/216 = 4/9 = 44.4% (rounded)
The probability is 90/216 = 5/12
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
With one roll of three dice, the probability is 7/8.
The probability that the sum is seven all three times is 1/216.
5/36 or 13.9%.
The probability is 90/216 = 5/12
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
With one roll of three dice, the probability is 7/8.
50%. There are three dice; each die has 6 faces.
The probability that the sum is seven all three times is 1/216.
The probability is 1 and you do not need Matlab to get that answer - only a little bit of thought.
5/36 or 13.9%.
There are 6 outcomes, a 2 is one of them so the probability is 1/6.
These are independent one has no bearing on the other
The probability of getting at least one prime number in two dice is 3/4.
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.