Odds of rolling ONE six - 6:1
Odds of rolling TWO sixes - 36:1
Odds of rolling two sixes, SIX times - 216:1
The probability of rolling a 3 on a die are 1/6. Since each roll is an independent event, the probability of rolling a 3 4 times in a row is (1/6)4 or 1/1296.The odds of something happening are the chances of it happening vs. the chances of it not happening. The chance of not rolling a 3 4 times in a row is 1-(1/1296) or 1295/1296.Therefore the odds are 1:1295
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
you have about a 42% chance for that to happen
The probability of rolling a six on a die 6 times in a row is 1 in 46,656, or 0.000021433. The calculate that, the probability of rolling one 6 is 1 in 6. Simply raise that to the sixth power to get 1 in 46,656.
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).
The odds of rolling a 7 are 1/6. The odds of rolling two in a row are 1/36. The odds of rolling an 11 are 1/18. The odds of rolling two in a row are 1/324. The odds of rolling doubles are 1/6. The odds of rolling double twice in a row are 1/36.
1/6 x 1/6 x 1/6 = 1/216 is the odds of getting three doubles in a row so I suppose the odds of not rolling three in a row is 215/216 or 99.54% chance.
1 in 12
The probability of rolling a 3 on a die are 1/6. Since each roll is an independent event, the probability of rolling a 3 4 times in a row is (1/6)4 or 1/1296.The odds of something happening are the chances of it happening vs. the chances of it not happening. The chance of not rolling a 3 4 times in a row is 1-(1/1296) or 1295/1296.Therefore the odds are 1:1295
The odds of rolling snake eyes (two ones) on a pair of dice is 1 in 36, since there are 36 possible outcomes when rolling two dice. To find the odds of rolling snake eyes twice in a row, you multiply the probabilities: ( \frac{1}{36} \times \frac{1}{36} = \frac{1}{1296} ). Therefore, the odds of rolling snake eyes twice in a row are 1 in 1296.
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
The odds of landing on Boardwalk with three doubles in a row in Monopoly are 1 in 1,296.
The probability of rolling doubles with 2 dice is 1 in 6, or about 0.1667. The probability of doing that 100 times in a row is 0.1667100 or about 1.531x10-78.
Assuming that there is only one 1 on the 100 faces, the odds are (1/100)3 or 10-6, that is 1 in a million.
The odds are 1/36