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How do you solve this 10 percent of m nd m plain candies are blue if a sample of 20 m nd ms is randomly selected find P of it will be more than 15 blue candies?
If 10% of plain M&Ms are blue and you have a sample of 20 M&Ms only two of them will be blue. If you need to have 15 blue M&Ms, then your sample size should be 150 M&Ms because 15 is 10% of 150.
If X is a normal random variable with standard deviation 4.00 and if the probability that X is more than 5.52 is 1271 then what is the mean of X?
Let M be the mean. P( X > 5.52) =0.1271 Standardize X by subtracting the mean and dividing by the standard deviation. z = (52.2-M) /4 From the normal distribution tables, P( z > 1.14 )=0.1271 Therefore, (52.2-M) / 4 = 1.14 Solve for M, the mean. 52.2-M = 4(1.14) = 4.56 M=52.2-4.56 =47.64
How do ecoligists use the technique of sampling to estimate population size?
There are many many ways. One method is called mark-recapture. The simplest method involves taking 2 samples. In the first sample, all the animals that are captured are marked (this can be leg bands, ear tags, toe clipping, or even using photoID in the case of whales/tigers). The size of this sample is called M to denoted that this is now our population of Marked animals. The second sample, which is collected at a later date, will usually (hopefully) contain some of the previously marked animals, and some animals that weren't previously caught. The size of the second sample is denoted n, and the number of marked animals in it is called m. But we want to know N - the total population size. We can assume that the ratio of marked animals in our second sample (m/n) is the same as the ratio of marked animals in the population (M/N). Therefore: M/N=m/n Rearrange it: N=(n*M)/m We know the values for M,n, and m so we can figure out N. This is the simplest case, and is know as the Lincoln-Peterson estimator. There are many extensions to this that allow for more samples etc.
How big an area on earth would one trillion peas cover?
I solve this problem in two steps: Step 1: How much space does one pea take up? Step 2: How much space does 1 trillion peas take up? 1) How much space does one pea take up? I will assume one pea would occupy a square area 5 mm by 5 mm, which equals 25 mm2. 2) A trillion peas, requires me to use scientific notation, 1 trillion = 10^12. So our trillion peas takes up 25 *1012 mm2. Now 1 m = 1000 mm, so 1 m2 = 10^6 mm2, and 1 km = 1000 m, so 1 km2 = 10^6 m2, so 10^12 mm2 = 1 km2. Now, 25 * 1012 mm (1 km2/1012 mm2) = 25 km2 is the area on earth that one trillion peas would cover. Remember: One thousand = 103, One million = 106, one billion = 109, one trillion = 1012 Also, when you find a problem that seems too big to solve, try finding a small problem to solve, which will help you to solve the bigger one.
How big is 500 meters squared?
I have some trouble understanding your question. I will answer the following questions: a) What is the area of a square, 500 m on a side? Ans: 500 x 500 = 250,000 m2. b) If I had a square with an area of 500 m2, what is the size of each side? sqrt(500) = 22.3 m
