The probability that you pick 3 white balls is 0.05 or 5%.
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EXPLANATION
The probability of first drawing a white ball is: P(W1) =
3/6.
The probability of drawing a white ball given the event that you already draw a
white ball in the first draw and not replacing it back is: P(W2│W1) =
2/5.
The probability of drawing a white ball on the third draw given the event that a
white ball was drawn in the first and in the second draw is: P(W3│(W
1UW2)) =
1/4
Now, the probability of drawing 3 white balls one by one with out replacement
(taking all 3 balls at a time gets the same analysis and result) is:
P(W1UW2UW3) =
P(W1)∙P(W
2│W1)∙P(W
3│(W
1UW2)) =
(3/6)∙(2/5)∙(1/4) =
1/20
=
0.05 =
5%.
2
If I have 3 red balls 3green balls 2 white balls & 5black all in one sack what is the probability of finding a white ball?
It is 0.2174, approx.
It is 1/7 if a ball is selected at random.
3/5 probability of a white ball being drawn.
The probability is zero, because there are no red balls in the bag.
2
If I have 3 red balls 3green balls 2 white balls & 5black all in one sack what is the probability of finding a white ball?
The probability of a simple event is the number of ways to succeed over the total possibilities. So, there are three white balls, and ten balls total. So: P(white) = 3/10
It is 0.2174, approx.
It is 1/7 if a ball is selected at random.
3/12*3/11 = 9/132, or 6.818%.
3/5 probability of a white ball being drawn.
The probability is: 55/200 or 11/40
17 out of 21
6/10 or reduced is 3/5
zero