The median is: 5
4
Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6
There is only one median in a set of values. If it is an odd amount of values, the median is the middle number. If there is an even amount of numbers, the median is the value halfway between the two middle numbers. So, in 1, 2, 3; the median is 2. In 1, 2, 3, 4; the median is 2.5, as that is halfway between 2 and 3.
I am guessing you are asking for an example of a set of numbers with these properties. Let's start with 5 numbers, so the median will be the middle number; say 1, 2, 3, 4, 5. The median is 3, but so is the mean. Now let's replace the 5 with 10. The median is still 3, but the mean is 4. To make the mode less than 3, let us change the 2 into a 1. Now the median is still 3, the mode is 1, and the mean is 3.8. So 1, 1, 3, 4, 10 will work.
For an odd number of data values, the median is the middle number, the [(n+1)/2]th numberi.e. for 7 data values, (7 +1)/ 2 = 4, and the 4th is the middle value, or median.*For an even number of values, the median is the mean of the two middle numbers,i.e. one-half the sum of the two middle values (add n/2nd value and n/2+1st values and divide by 2).Examples:Median of 1, 3, 2 reordered as 1, 2, 3 = median 2Median of 6, 5, 3, 1 reordered as 1, 3, 5, 6 = median 4 (3+5 divided by 2)
2.5 is the median
2
The median is 4.
the answer is 3
2 or 3
2.5
The median is the middle value. 2 , 2 , 3 , 4 , 5 Median = 3
The data {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7} has: Median: Thee are 16 data items, so the median is the mean average of the middle two, ie the 8th and 9th numbers: median is (3 + 3) / 2 = 3 Mean: (1 + 1 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 6 + 7) ÷ 16 = 55 ÷ 16 = 37/16 = 3.4375
If that's 1, 2, 3, 4, 7, 7, 8, the median is 4.
1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4
it is 3
4