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Q: What is the formula of surface area?

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Perimeter = area + b1 + b2 + c P = a + b1 + b2 + c

The surface area of a cylinder can be found using the following formula - SA = 2(Pi*r2) + (2*Pi*r)*(H) Pi = Approximately 3.14 r = Radius of the base of the cylinder H = Height of the cylinder

The surface area is 1,385.4 cm2

Do you mean the surface area of the box? If so... What you do is break the surface area into 6 rectangles: Two rectangles have sides of length 6.3 and 12.6 inches. Two rectangles have sides of length 6.3 and 4.2 inches. Two rectangles have sides of length 12.6 and 4.2 inches. Find the area of each of the six rectangles (using the standard formula for the area of a rectangle, A = W x H), and add up all six. The sum of the areas of the six rectangles will be the surface area of the box. Since the lengths of the sides are in inches, the area will already be in square inches, and therefore you don't have to "turn it into square inches".

726 cm2

Related questions

False. The surface area formula for a right cone is not the same as the surface area formula for an oblique cone.

what is the formula to finding the total surface area of a rhomboid?!

The formula for the surface area of a circle is pi times the square of the radius. The formula for the surface area of a triangle is base times height, divided by 2. The formula for the surface area of a square or rectangle is length times width.

The formula for the surface area of a sphere is: 4 pi r 2

It depends on the formula that describes the surface itself. "Curved surface area" is not enough information to answer the question.

Well, the formula for the surface area for one sphere is 4∏r2So if you have two identical spheres, the formula for the surface area of both would be 8∏r2

Given the surface area, where S=surface area, the formula for finding the volume isV = √(S / 4pi)

Surface area = 4*pi*radius2

derivation of surface area of cuboid

Hi, Surface Area formula of cube is 6a2.

Curved Surface Area = 2πr2Total Surface Area= (2πr2) + (πr2) = 3πr2

No, the formula is far from simple - requiring elliptical integrals.

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