The median of 2, 3, 4, 5, 6, 6, and 9 is 5. The median is the middle value of the list. In this case, three numbers are below 5, and three numbers are above 5. Thus, it is the middle number.
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The median is: 5
I am guessing you are asking for an example of a set of numbers with these properties. Let's start with 5 numbers, so the median will be the middle number; say 1, 2, 3, 4, 5. The median is 3, but so is the mean. Now let's replace the 5 with 10. The median is still 3, but the mean is 4. To make the mode less than 3, let us change the 2 into a 1. Now the median is still 3, the mode is 1, and the mean is 3.8. So 1, 1, 3, 4, 10 will work.
Mean: 5 Median: 5 Mode: 3
For an odd number of data values, the median is the middle number, the [(n+1)/2]th numberi.e. for 7 data values, (7 +1)/ 2 = 4, and the 4th is the middle value, or median.*For an even number of values, the median is the mean of the two middle numbers,i.e. one-half the sum of the two middle values (add n/2nd value and n/2+1st values and divide by 2).Examples:Median of 1, 3, 2 reordered as 1, 2, 3 = median 2Median of 6, 5, 3, 1 reordered as 1, 3, 5, 6 = median 4 (3+5 divided by 2)
The median is the middle value. 2 , 2 , 3 , 4 , 5 Median = 3
The median is 4.
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The median is 4.5
When there is an even number of data items the median is the mean average of the middle two. → median of {2, 3, 4, 5, 7, 9} = (4 + 5)/2 = 9/2 = 4.5
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(2 + 2 + 3 + 5) / 4 = 12 / 4 = 3
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2.5 is the median
The data {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7} has: Median: Thee are 16 data items, so the median is the mean average of the middle two, ie the 8th and 9th numbers: median is (3 + 3) / 2 = 3 Mean: (1 + 1 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 6 + 7) ÷ 16 = 55 ÷ 16 = 37/16 = 3.4375
1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4
The median is: 5