If you throw a single fair coin multiple times, the probability of getting NO head is:For 1 throw: 1/2
For 2 throws: 1/2 squared = 1/4
For 3 throws: 1/2 cubed = 1/8
etc.
The probability of getting AT LEAST ONE head is the complement; for example, for 3 throws, it would be 1 minus 1/8.
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The probability of at least one head when you toss an unspecified number of coins an unspecified number of times is indeterminate.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.
It is 0.75
Let put the question in an other way : obtaining at least one head is the contrary of obtaining two tails at the same time. The probability to obtain one tail with first coin is 1/2, the probability to obtain one tail with the other is also 1/2, so the probability to obtain one tail on each coin is 1/2x1/2 = 1/4 Thus the probability to obtain at least one head is 1-1/4=3/4
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375