1 out of 7
I think so!
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if we assume that the probability for a girl being born is the same as a boy being born: (1/2)^6 = 0.015625 = 1.5625%
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
1- P(identical) - P(fraternal) =1-0.004-0.023 =0.973 The probability of being a identical or fraternal twin plus the probability of not being a twin has to add to 1. so 1- probability of being twins=probability of not being a twin ;-)
the probability is 1(being the maximum)- the probability you have allredy got. the answer is 0.6
Well, darling, there are 7 days in a week, so the probability of being born on a Wednesday is 1 out of 7, which simplifies to about 14.3%. So, if you fancy being a midweek baby, Wednesday is your lucky day!