With two dice the following totals are possible
....... Dice A .. Dice B
So, there are 36 different combinations of how the dice might land and 6 of those total 7. Therefore it is 6 chances in 36 that you'll get 7, which reduced to 1 in 6.
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
5/36
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
There are 36 permutations of two dice.1 Of these 4 have a sum of 9, specifically 36, 45, 54, and 63. Therefore, the probability of throwing a sum of 9 on two dice is 4 in 36, or 1 in 9, or about 0.1111. ---------------------------------------------------------------------------------- 1It does not matter it you throw one die two times or two dice once. Since these are independent events, the probabilities are the same either way.
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
It is 30/36 = 5/6
The probability is zero. The largest possible sum on two dice is 12.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
Assuming these are regular dice, the probability is 1.
It is 5/36.
The probability is 27/216 = 3/8 = 0.125
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
With two normal six-sided dice, the maximum sum can only be 12 (6 x 2 dice), so there is zero probability of rolling a sum that adds to 16.
5/36
35/36