It depends on what the questionis and what you can choose from.
Probability, P, of 70% or more correct (7 or more correct) is: P(7) + P(8) + P(9) + P(10). See the related link; N=10, P = 0.5, and K = 7, 8, 9, & 10. Therefore the probability is: .11719 + .04395 + .00977 + .00098 = .17189 or approximately 17.2% probability 7 or more correct.
6 to 1. (That is, 6 incorrect to 1 correct.) This is equaivalent to a probability of 1/7 or a 14% chance of guessing the correct answer.
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
Probability, P, of 70% or more correct (7 or more correct) is: P(7) + P(8) + P(9) + P(10). See the related link; N=10, P = 0.5, and K = 7, 8, 9, & 10. Therefore the probability is: .11719 + .04395 + .00977 + .00098 = .17189 or approximately 17.2% probability 7 or more correct.
6 to 1. (That is, 6 incorrect to 1 correct.) This is equaivalent to a probability of 1/7 or a 14% chance of guessing the correct answer.
The probability is 7/36
7 in 12, or about 0.5833.
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
p = 1 / Time » 2 X 10-7
On a single roll of a normal die the probability of getting a 7 is 0.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128