In three tosses, the probability is 3/8.
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The probability of getting two tails when tossing a coin is zero, because the coin can only have one result. If, one the other hand, you toss the coin twice, then the probability of getting two tails is 0.25, i.e. the probability of one tail, 0.5, squared.
25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25
The probability of two tails on two tosses of a coin is 0.52, or 0.25.
Let put the question in an other way : obtaining at least one head is the contrary of obtaining two tails at the same time. The probability to obtain one tail with first coin is 1/2, the probability to obtain one tail with the other is also 1/2, so the probability to obtain one tail on each coin is 1/2x1/2 = 1/4 Thus the probability to obtain at least one head is 1-1/4=3/4
lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.