The probability of getting two tails when tossing a coin is zero, because the coin can only have one result. If, one the other hand, you toss the coin twice, then the probability of getting two tails is 0.25, i.e. the probability of one tail, 0.5, squared.
25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25
The probability of two tails on two tosses of a coin is 0.52, or 0.25.
Let put the question in an other way : obtaining at least one head is the contrary of obtaining two tails at the same time. The probability to obtain one tail with first coin is 1/2, the probability to obtain one tail with the other is also 1/2, so the probability to obtain one tail on each coin is 1/2x1/2 = 1/4 Thus the probability to obtain at least one head is 1-1/4=3/4
lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.
50%
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.
The probability of getting two tails when tossing a coin is zero, because the coin can only have one result. If, one the other hand, you toss the coin twice, then the probability of getting two tails is 0.25, i.e. the probability of one tail, 0.5, squared.
25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25
The probability of two tails on two tosses of a coin is 0.52, or 0.25.
With two flips of a coin you can get two heads, two tails, a head and a tail, or a tail and a head. There are a total of four different possible outcomes, and three of them have at least one head. That's 3 out of 4, or 3/4ths. It's also 0.75 which is the probability of getting at least one head with two flips of a coin. Note that as we use the term probability here, it is zero (no chance it can happen at all), or one (it must happen), or something in between. A probability appears in the form of a fraction or decimal, and has no units attached to it.
The flip of a fair coin is 0.5 heads and tails, so you want the probability of head & head. This probability of garlic, garlic two consecutive tosses is 0.5 * 0.5 = 0.25.
Let put the question in an other way : obtaining at least one head is the contrary of obtaining two tails at the same time. The probability to obtain one tail with first coin is 1/2, the probability to obtain one tail with the other is also 1/2, so the probability to obtain one tail on each coin is 1/2x1/2 = 1/4 Thus the probability to obtain at least one head is 1-1/4=3/4
lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.
It is 3/8 = 0.375
The probability is 1/4
It is 1/2.