"Puzzle" has 6 letters, and 2 of them are vowels. So the odds of choosing a vowel are 2/6, which equals 1/3, which is one-third or 33.33%.
The probability for a single random choice, is 6/13.
4/11
The word "space" consists of 5 letters: s, p, a, c, and e. If you are choosing one letter at random from these 5 letters, the probability of choosing any specific letter is 1 out of 5, or 20%. If you're looking for the probability of choosing a vowel (a or e), it would be 2 out of 5, or 40%.
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
To work out probability you have to know the number of possible options, and how many of those options meet the criteria. In this case there are 26 possible options (all the letters) and 21 that meet the criteria (21 non-vowels). The probability is the number that match divided by the total number possible. In this case it would be 21/26. This comes out to approximately 0.80769. Thus the probability that a letter picked at random is not a vowel is 0.80769
The answer depends onthe alphabet that you chose,whether or not you consider y to be a vowel,whether or not each letter is equally likely to be chosen (eg not from a bag of scrabble tiles), andwhether or not the choice was random.If a choice was random, from equal numbers of letters from the modern Roman alphabet and y is not considered a vowel then the answer is 5/26.
3 in 8, 0.375, if you consider the y as a consonant, 4 in 8, 0.5, if not.
Probability is given as Desired Outcomes divided by total number of outcomes. For the probability of picking a vowel, desired outcomes are : a,e,i,o,u (5) Total no. of outcomes is the entire alphabet set from a to z (26) Hence, the required probabilty is 5/26
if you only consider the vowels to be aeiou, then the answer is that you have a 5 out of 26 (or .19%) chance.
The word 'probability' has 11 letters and 5 of them are vowels (including the 'y'). Therefore the probability of picking a vowel is 5/11.
There are 5 letters in the set {a, b, c, d, e}, and 2 of these letters are vowels (a, e). Therefore, the probability of randomly choosing a vowel from this set is the number of favorable outcomes (2 vowels) divided by the total number of possible outcomes (5 letters), which equals 2/5 or 0.4.
What is the probability of the spinner landing on CorB