P(8 or greater on two dice) = P(2 on first and 6 on second) + P(3 on first and at least 5 on second) + P(4 on first and at least 4 on second) + P(5 on first and at least 3 on second) + P(6 on first and at least 2 on second) = (1/6 * 1/6) + (1/6 * 2/6) + (1/6 * 3/6) + (1/6 * 4/6) + (1/6 * 5/6) = (1 + 2 + 3 + 4 + 5)/36 = 15/36
P(8 or greater on two dice) = 15/36, or 5/12.
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The probability is 1.
The probability is 26/36 or 13/18
The answer depends on what you are rolling: three or more ordinary dice, or fewer dice with non-standard numbers on them, or a die with some other shape.
5/36
In the case of dice, greater than three, means 4,5 or 6. So, obviously, three cases out of 36.