1/6 x 1/6 x 1/6 = 1/216
1 in 6 = rolling a 2 5 in 6 = not rolling a 2
Assuming you're using 6-sided dice, The probability of rolling less than 4 on one die is 1/2. To roll 3 dice and get less than 4 on 2 (and only 2) of them is 3/8.
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
Probability of ' 5 ' on the first roll = 1/6Probability of ' 3 ' on the second roll = 1/6Probability of ' 5 ' followed by ' 3 ' = 1/6 x 1/6 = 1/36 = 27/9 percent
It's deduction. You can find the odds of something happening by first finding out the odds of that something not happening. That is converse probability. For instance the odds of rolling a "3" on a 6 sided die. Using converse probability would be 5/6 (5 sides are not the number "3"). 6/6 (six sides in all) - 5/6 = 1/6 is the odds of rolling that "3".
1/3
1 in 6 = rolling a 2 5 in 6 = not rolling a 2
Assuming you're using 6-sided dice, The probability of rolling less than 4 on one die is 1/2. To roll 3 dice and get less than 4 on 2 (and only 2) of them is 3/8.
The probability of rolling a 3 is 1/6.
If you keep rolling the die, the probability is 1. If you require a 3 and a 4 in the first two rolls, the answer is (1/6)*(1/6) = 1/36
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
Probability of ' 5 ' on the first roll = 1/6Probability of ' 3 ' on the second roll = 1/6Probability of ' 5 ' followed by ' 3 ' = 1/6 x 1/6 = 1/36 = 27/9 percent
It's deduction. You can find the odds of something happening by first finding out the odds of that something not happening. That is converse probability. For instance the odds of rolling a "3" on a 6 sided die. Using converse probability would be 5/6 (5 sides are not the number "3"). 6/6 (six sides in all) - 5/6 = 1/6 is the odds of rolling that "3".
A standard die has no memory and so the probability of rolling an even number is always a half. If you did not know that the die was standard and were using the fact that 7 out of 12 rolls were even as an empirical estimate for a loaded die then the answer is 7/12.
It is 4/36 or 1/9.
If you're rolling a single six sided die: 1/6If you're flipping a coin, and using three sequential flips to represent binary digits: 1/8If you're drawing a card from a deck: 1/13If you're picking a random number from 1 to N: 1/NIf you're rolling two six-sided dice: 1/9If you're doing something else, then you'll need to be less vague in your question.
Joint probability is the probability that two or more specific outcomes will occur in an event. An example of joint probability would be rolling a 2 and a 5 using two different dice.