It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
It is a certainty. If the die is rolled often enough, the probability that two consecutive rolls show a six is 1.
There are twenty six ways out of thirty six possible rolls of two dice to hit a number less than nine OR a seventy two percent probability.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
If you roll the die often enough, the probability of getting a 2 ones in a row is 1. In only 2 rolls, the answer is (1/6)*(1/6) = 1/36
The answer depends on how many rolls. If there were n rolls, then the probability is n*(1/6)*(5/6)n-1/[1 - (5/6)n]
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
It is a certainty. If the die is rolled often enough, the probability that two consecutive rolls show a six is 1.
It is 0.3292, approx.
What is the probability of 1, 6, 4, on 3 rolls of a die
There are twenty six ways out of thirty six possible rolls of two dice to hit a number less than nine OR a seventy two percent probability.
The probability that a six will never show up in three rolls of a die is 125 in 216. The probability that a six will not show up in one roll is 5 in 6. Raise that to the third power to get 125 in 216.
1/4? ...
Prob(No sixes in 6 rolls) = [Prob(Not a six in a roll)]6 = (5/6)6 = 0.3349
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.
One way of finding the probability is to carry out an experiment repeatedly. Then the estimated experimental probability is the proportion of the total number of repeated trials in which the desired outcome occurs.Suppose, for example you have a loaded die and want to find the probability of rolling a six. You roll it again and again keeping a count of the total number of rolls (n) and the number of rolls which resulted in a six, x. The estimated experimental probability of rolling a six is x/n.