Assuming it is a standard Poker deck with 52 cards and 4 aces
The probability of getting your first card an ace is = 4/52
Over here you need to reread your questions. There are something you need to know before i continue - when you draw your second card, did you return the first card back into the pile? lets say if you draw an ace of spades, would you be able to redraw it again for the second card?
If the first ace is return to the pile:
probability of getting a second ace is also 4/52
so the total probability of getting both cards an ace is (4/52 x 4/52)
If the first ace is not return to the pile:
probability of getting a second ace is now 3/51
note that removing one ace also removes one card from the pile. total card is now 51 with 3 aces only
so the total probability of getting both cards an ace is (4/52 x 3/51)
hope i help.
If only two cards are drawn from a standard deck of cards, with the first card replaced before drawing the second, the answer is 0.005917 (approx). If the first card is not replaced, the probability increases to 0.006033.
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
The probability of drawing an Ace from a 52 card deck is 4/52 or 1/13.
There are total of 52 cards in a deck and 4 of those are Aces. Therefore, there are 48 card non-ace. The probability of drawing one card that is not an ace will be 48 divided by 52. The answer is 12/13.
4/221
Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"
The answer depends on whether or not the first card is replaced before the second is drawn.
An independent probability is a probability that is not based on any other event.An example of an independent probability is a coin toss. Each toss is independent, i.e. not related to, any prior coin toss.An example of a dependent probability is the probability of drawing a second Ace from a deck of cards. The probability of the second Ace is dependent on whether or not a first Ace was drawn or not. (You can generalize this to any two cards because the sample space for the first card is 52, while the sample space for the second card is 51.)
The probability that two cards drawn from a deck of cards being an Ace followed by a King is 1 in 13 (for the Ace) times 4 in 51 (for the King) which is equal to 4 in 663.
If only two cards are drawn from a standard deck of cards, with the first card replaced before drawing the second, the answer is 0.005917 (approx). If the first card is not replaced, the probability increases to 0.006033.
The probability of drawing two cards that are a 2 when the first card is an Ace is zero, because a two is not an Ace. They are mutually exclusive events. If this is not clear, consider the probability of rolling a seven on one roll of one six sided die. That probability is also zero - it will not happen.
The probability of drawing a Ace from a standard deck of 52 cards if one Ace is missing is 3 in 51, or about 0.05882. If the missing card is not an Ace, then the probability is 4 in 51, or about 0.07843.
The probability of drawing a jack, queen, or king on the second draw if the first draw was an ace (without replacement) is (4 + 4 + 4) in (52 - 1) or 12 in 51, which is 4 in 17, or about 0.2353.
A Black Jack is an Ace and a face card (Ten through King). The probability of drawing a Black Jack as the first two cards from a standard deck is 4 in 52 times 16 in 51, which is 0.0241 (Ace First), or 16 in 52 times 4 in 51, which is also 0.0241 (Ace Second).
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
Probability not ace is 1 minus probability of an ace which is 4/52. So, 1 - 4/52 is 48/52 or 12/13.
The probability of drawing an Ace from a 52 card deck is 4/52 or 1/13.