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The probability is 4/52 for the first ace and 3/51 for the second.

So the probability of 2 aces is 4/52 x 3/51 = 1/221

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What is the probability of beind dealt five aces from a standard 52 card deck?

Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.


What is the probability of being dealt 4 aces from a standard 52 card deck?

The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6


What is the probability of getting dealt two aces in a deck of cards?

The odds are 220:1 of being dealt pocket aces.


How often do you get dealt pocket aces in a game of poker?

The probability of being dealt pocket aces in a game of poker is approximately 1 in 221 hands.


What is the combined probability of being dealt a face card and then a three as the second card from a standard 52 card deck?

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If dealt one card from a standard 52 card deck what is the probability of being dealt an ace or a 9?

Aces and 9s are disjoint events, so the probability of either is the sum of the probabilities of each. P(A or 9) = P(A) + P(9) = 1/13 + 1/13 = 2/13


You are dealt one card from a 52 deck of cards what is the probability of being an ace?

Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent


What is the probability of getting 4 aces when dealt with 13 cards?

To find the probability of being dealt exactly 4 aces in a 13-card hand from a standard 52-card deck, we can use the hypergeometric distribution. The total number of ways to choose 4 aces from 4 available is ( \binom{4}{4} = 1 ), and the number of ways to choose the remaining 9 cards from the 48 non-aces is ( \binom{48}{9} ). The total number of ways to choose any 13 cards from 52 is ( \binom{52}{13} ). Thus, the probability is given by ( \frac{1 \times \binom{48}{9}}{\binom{52}{13}} ).


What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?

The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%


What hand in poker has the highest probability of beating pocket aces?

The hand in poker with the highest probability of beating pocket aces is a pair of aces.


What is the probability that you will pick two aces in a row out of a 52 card deck?

The probability of drawing two Aces from a standard 52 card deck is (4 in 52) times (3 in 51) or (12 in 52851) or (4 in 17617) or about 0.0002271.


The probability that two cards drawn from a deck of cards are both aces?

The probability of drawing two Aces from a standard deck of 52 cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.00452.