2/9
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!
The probability is 0. Consider the event of tossing a coin . The possible events are occurrence of head and tail. they are mutually exclusive events. Hence the probability of getting both the head and tail in a single trial is 0.
It is 1/12.
This is correct. For example the probability of tossing a coin so that it comes up heads is 1/2 and the probability that it comes up tails is also 1/2. The probability that it will come up either heads or tails is 1.
Depends on if you are talking about probability. If so then yes. If not then 100 coins is more than 1 coin.
The probability for that is (1/2)4 = 1/16.
The probability would be once in 128 attempts. You don't have to toss seven coins simultaneously. the 7 tosses just have to be independent of one another.
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A compound event, in probability theory is an event which is made up of two (or more) simpler events. Thus, tossing two coins in a compound event made up of tossing one coin and tossing another coin. Getting soaked in rain consists of the simple events that it rains (where you are) and you are outdoors without an umbrella (at that time).
2/9
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!
Tossing a coin ten times is a [repeated] experiment or trial. It is neither empirical nor theoretical probability.
One in eight, or 12.5%.
The probability is 0. Consider the event of tossing a coin . The possible events are occurrence of head and tail. they are mutually exclusive events. Hence the probability of getting both the head and tail in a single trial is 0.
It is 1/12.
The probability of tossing two coins one time and not getting two heads is 3/4 or 75%. The possible out comes of this are: HH, HT, TH, TT. There is only one way to get two heads, out of four possible results. Another, faster way to do this problem would be to multiply the probability of getting one head on one coin (1/2) by the probability of getting a head on another coin (also 1/2). This will result in 1/4. Because you want every result BUT this one, subract this answer from one. You will get the an answer of 3/4. This may not seem like a faster method when writing it out, but with a larger number of coins it would save a lot of time, because you do not have to go through all of the combinations.