Since each event is independent, the probability remains at 0.5.
Two ways to think about it: 1: 25% both heads 50% one of each 25% both tails -or- 2: 25% heads/heads 25% heads/tails 25% tails/heads 25% tails/tails
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
For each of the coins, in order, you have two possible outcomes so that there are 2*2*2*2 = 16 outcomes in all.
Each toss has 2 possible results.A series of 3 tosses has (2 x 2 x 2) = 8 possible overall scenarios.Three scenarios have exactly two tails: TTH, THT, and HTT.So the probability is 3/8 = 37.5% .
There are 2 coins, 1 and 2. Each has two possibilities, H or T. The possibilities are: 1H, 2H 1H, 2T 1T, 2H 1T, 2T Each possibility has an equal chance of happening. The chance of tossing at least one head is 3/4.
5 independent events, each of them with a probability of 1/2; you need to multiply all together, so you get (1/2) to the power 5.Note: any other specific combination you can get when throwing a coin 5 times - for example, head, tails, head, tails, head - will have the same probability.
lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.
Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT
Because you are thinking permutations rather than combinations. There are four permutations of two coins, but there are only three combinations, because it does not matter which coin is heads and which coin is tails. As a result, the combination of heads and tails has a 0.5 probability, while two heads or two tails each have a 0.25 probability.
The chance for each toss is 1/2. The chance of all three flips being tails is 1/2 * 1/2 * 1/2 = 1/8. So the probability of at least one head is 7/8.
Ignoring the very small probability of the coins landing on their edge, the probability of header = probability of tails = 1/2 Pr(2 tails) = ₃C₂ × ½² × ½¹ = 3 × ½³ = 3/8 --------------------------------------------- This is small enough to list the possible outcomes: Outcomes = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} (In each outcome the first letter is the first coin, 2nd letter the second coin and the third letter the third coin, which can be either H = Heads, or T = Tails.) There are 8 outcomes of which {HTT, THT, TTH} 3 satisfy having 2 tails → pr(2 tails) = 3/8