25% or 1 out of 4
(You can use a Punnett Square for that and/or other questions like it.)
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
In a heterozygous offspring, the recessive allele is present but not expressed because the dominant allele masks its effects.
Heterozygous induviduals pass the dominant and recessive alleles to offspring
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
No. Parents with the dominant phenotype might be heterozygous in their genotype. This means they could carry both the dominant and recessive allele for a trait. So they could both pass the recessive allele to an offspring, who would then have the homozygous recessive genotype and recessive phenotype.
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.
It depends on the parents. The parent could have two dominant genes which would give a 0% chance of the offspring being recessive. The only way that the offspring could have a recessive characteristic is if the both parents have one dominant and one recessive gene, a 25% chance. The chance that both parents would pass on the recessive gene (if they have one dominant and recessive gene) is also 25%, because there is a 50% chance for each parent.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.