25% or 1 out of 4
(You can use a Punnett Square for that and/or other questions like it.)
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
In a heterozygous offspring, the recessive allele is present but not expressed because the dominant allele masks its effects.
Heterozygous induviduals pass the dominant and recessive alleles to offspring
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
Parents with the dominant phenotype can have offspring with the recessive phenotype if both parents are heterozygous carriers of the recessive allele. In this case, there is a 25% chance for their offspring to inherit two copies of the recessive allele and display the recessive phenotype.
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
The offspring will all be heterozygous for the trait, carrying one dominant and one recessive allele. This is known as a monohybrid cross, resulting in all offspring displaying the dominant trait phenotypically but carrying the recessive allele genotypically.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.
The probability of a homozygous recessive offspring resulting from a cross between two homozygous dominant individuals is 0%. This is because both parents can only pass on dominant alleles, so there is no possibility of a recessive allele being passed to the offspring.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.