25% or 1 out of 4
(You can use a Punnett Square for that and/or other questions like it.)
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
Heterozygous induviduals pass the dominant and recessive alleles to offspring
If both the individuals are heterozygous dominant then the probability of recessive (homozygous) phenotypic offspring would be 1:4
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
if a trait is recessive, it can only be expressed if its other trait is recessive as well. If the other trait in the genotype is dominant, it will block the recessive factor. But if both are recessive, they will be able to be seen in the offspring.
a homozygous trait is when an offspring has either both dominant genes or both recessive genes from its parents. a heterozygous trait is when an offspring has both dominant and recessive genes. for example: a long-tailed cat is dominant and a short-tailed cat is recessive. the long-tailed cat (homozygous dominant) had offsprings with the short-tailed cat (homozygous recessive). by doing the punnett square, 100% of their offspring will be heterozygous.
A living thing with a dominant and a recessive gene for a trait is heterozygous. This individual will display the dominant phenotype for that trait but may have offspring that display the recessive trait.