Area to the left of z = -1.72 = area to the right of z = 1.72
That is ALL the "working" that you will be able to show - unless you are into some serious high level mathematics. Most school teachers and many university lecturers will not be able to integrate the standard normal distribution: they will look it up in tables. (I have an MSc in Mathematical Statistics and I could do it but not without difficulty).
Pr(z < -1.72) = 0.042716
0.088508
One standard deviation
The Z value is negative, but area is always positive.
It is 0.877
The area under the normal distribution curve represents the probability of an event occurring that is normally distributed. So, the area under the entire normal distribution curve must be 1 (equal to 100%). For example, if the mean (average) male height is 5'10" then there is a 50% chance that a randomly selected male will have a height that is below or exactly 5'10". This is because the area under the normal curve from the left hand side up to the mean consists of half of the entire area of the normal curve. This leads us to the definitions of z-scores and standard deviations to represent how far along the normal curve a particular value is. We can calculate the likelihood of the value by finding the area under the normal curve to that point, usually by using a z-score cdf (cumulative density function) utility of a calculator or statistics software.
0.088508
One standard deviation
-1.43 (approx)
The Z value is negative, but area is always positive.
It is 0.839
To find the area under the normal distribution curve between z = 1.52 and z = 2.43, you can look up the z-scores in a standard normal distribution table or use a calculator. The area to the left of z = 1.52 is approximately 0.9357, and the area to the left of z = 2.43 is approximately 0.9925. Subtracting these values gives an area of approximately 0.9925 - 0.9357 = 0.0568. Thus, the area between z = 1.52 and z = 2.43 is about 0.0568.
It is 0.877
The area is 0.008894
To find the area under the standard normal curve between -1.33 and the mean (0), we can use the standard normal distribution table or a calculator. The area to the left of -1.33 is approximately 0.0918. Since the total area under the curve is 1 and the curve is symmetrical around the mean, the area between -1.33 and 0 is about 0.5 - 0.0918 = 0.4082. Thus, the area under the curve from -1.33 to the mean is approximately 0.4082.
To find the proportion of a normal distribution corresponding to z-scores greater than +1.04, you can use the standard normal distribution table or a calculator. The area to the left of z = 1.04 is approximately 0.8508. Therefore, the proportion of the distribution that corresponds to z-scores greater than +1.04 is 1 - 0.8508, which is approximately 0.1492, or 14.92%.
In a normal distribution half (50%) of the distribution falls below (to the left of) the mean.
Approx 78.88 % Normal distribution tables give the area under the normal curve between the mean where z = 0 and the given number of standard deviations (z value) to its right; negative z values are to the left of the mean. Looking up z = 1.25 gives 0.3944 (using 4 figure tables). → area between -1.25 and 1.25 is 0.3944 + 0.3944 = 0.7888 → the proportion of the normal distribution between z = -1.25 and z = 1.25 is (approx) 78.88 %