In a normal distribution half (50%) of the distribution falls below (to the left of) the mean.
The answer will depend on what the distribution is. Non-statisticians often assum that the variable that they are interested in follows the Standard Normal distribution. This assumption must be justified. If that is the case then the answer is 81.9%
Pr(Z > 1.16) = 0.123
THe 75th percentile
In a normal distribution, approximately 95% of the population falls within 2 standard deviations of the mean. This is known as the 95% rule or the empirical rule. The empirical rule states that within one standard deviation of the mean, about 68% of the population falls, and within two standard deviations, about 95% of the population falls.
The standard deviation provides in indication of what proportion of the entire distribution of the sample falls within a certain distance from the mean or average for that sample. If your data falls on a normal (or bell shaped) distribution, a SD of 1 indicates that about 68% of your data points (scores or whatever else) fall within 1 point (plus or minus) of the average (mean) of the data, and 95% fall within 2 points.
The answer will depend on what the distribution is. Non-statisticians often assum that the variable that they are interested in follows the Standard Normal distribution. This assumption must be justified. If that is the case then the answer is 81.9%
By definition, the 1st 6-tile is the point below which 1/6 of the population falls (irrespective of which distribution is involved). The 2nd 6-tile is the point below which 2/6 of the population falls. This is 100 * 1/3 ~ 33.3% of the population.
0% of a normal (of any) distribution falls between z 1.16 and z 1.16. 1.16 - 1.16 = 0.
It is 0.017864
Zero.
2
Pr(Z > 1.16) = 0.123
A condition in which the number of lymphocytes falls below normal levels.
-0.35
Approx 0.995
Although I cannot prove it, I doubt that there is a nice closed-form expression for this quantity; it's probably not a rational number. It's value is approximately 0.0227501319482. (Using Python code.)
THe 75th percentile